Quin's velocity is given by the resultant of the two velocities. If we assume east as positive direction, the two velocitiies are:
[tex]v_q =+1.6 m/s[/tex] is Quin's velocity in his reference frame
[tex]v_b=-0.3 m/s[/tex] is the belt velocity (with a negative sign since it is due west)
Therefore, the resultant is
[tex]v_T=v_q+v_b=+1.6 m/s-0.3 m/s=+1.3 m/s[/tex]
and the sign tells us the velocity is due east.
