We know that
if the club includes one set of identical triplets wearing matching clothes
then
the number of different arrangements that are possible is
10! / 3! = (10*9*8*7*6*5*4*3!)/3!
=604,800
The answer is
604,800
Answer:
604,800 different arrangements.
Step-by-step explanation:
The number of ways 10 objects can be arranged normally is 10!
It if there were 3 identical objects that all look similar, a number of the arrangements obtained for 10 objects will end up being similar, we account for this condition by dividing the total number of arrangements by the number of ways those 3 identical objects can be arranged on their own; 3!
So, for this question, the number of arrangements of 10 students possible if it includes one set of identical triplets wearing matching clothes will be
(10!/3!) = 604,800 different arrangements.
Hope this Helps!!!
