Question

Please answer the question!!?

Answer 1

g(x) = (x-3)^2 - 1 or D

Answer 2

Answer:

d). $g(x)= (x -3)^{2} -1$

Step-by-step explanation:

The original function $f(x) = x^{2}$ began from the origin mean that when x=0 the is going to be y=0

Using the standard equation  quadratic function:

$y= a*(x-h)^{2} +k\\h= 3$ ,  $k=-1$, $a=1$

Solving:

$y=1*(x-3)^{2} + (-1)\\y=(x-3)^{2} -1$

The second function have origin in the point (3,1) so making the function x=3

$g(x)= (x -3)^{2}-1\\g(3)= (3 -3)^{2}-1\\ g(3)=-1$