Question

Find the common difference of the arithmetic sequence.2, 1 8/9, 1 7/9,1 2/3, . . .
a.9b.-1/9c.-9d.1/9

Answer 1

For this case we have the following arithmetic sequence:
 2, 1 8/9, 1 7 / 9,1 2/3,. . .
 The common difference is given by the difference between two consecutive terms of the series.
 Therefore, for this case we have:
 $(1 \frac{8}{9}) - 2$
 Rewriting:
 $(1 \frac{8}{9}) - 2 = (1 + \frac{8}{9}) - 2$
 $(1 \frac{8}{9}) - 2 = -1 + \frac{8}{9}$
 $(1 \frac{8}{9}) - 2 = -\frac{9}{9} + \frac{8}{9}$
 $(1 \frac{8}{9}) - 2 = \frac{-9+8}{9}$
 $(1 \frac{8}{9}) - 2 = \frac{-1}{9}$
 Answer:
 The common difference of the arithmetic sequence is:
 b.-1/9