Question

If 43 of the 148 reams of paper purchased by a department are used, what is the percentage that remains?

Answer 1

First, calculate how many reams remain
remaining = 148 - 43
remaining = 105
There are 105 reams of paper remains

Second, change 105 reams into percentage
p = $\dfrac{105}{148} \times 100 \%$
p = $\left(\dfrac{105 \times 100}{148}\right) \%$
p = $\left(\dfrac{10,500}{148}\right) \%$
p = 70.945945945...%
to the nearest tenth
p = 70.9%

The percentage of paper remains is approximately 70.9%

Answer 2

This question is solved using the concept of percentage.

Doing this, we get that the percentage that remains 70.95%.

Percentage:

The percentage of a relative to b is given by:

$P = \frac{100a}{b}$

43 of the 148 reams of paper purchased by a department are used

Thus 148 - 43 = 105 remain, out of 148, and the percentage is:

105*100%/148 = 70.95%

The percentage that remains is 70.95%.

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