Question

Solve the equation. x^2 = 160

A $\frac{+}{}$ 16 ${ \sqrt{10} }$

B $\frac{+}{} 4 \sqrt{10}$


C 14


D -14, 14

Answer 1

square root both sides and don't forget to get the positive and negative roots
x=+/-$\sqrt{160}$

$\sqrt{160}$=$\sqrt{16}$ times $\sqrt{10}$

$\sqrt{16}$=+/-4
 
answer is
+/-4$\sqrt{10}$

answer is b

Answer 2

$x^2 = 160 \\ \\ x = \pm \sqrt{160} \\ \\ x = \pm 4 \sqrt{10}$

The final result is: x = ±4 √10 or B.