Question

The amount of heat needed
to raise 2.0 kg of a substance by 80 K is 33 kJ. What is the specific heat of
the substance?

Answer 1

Q = mcθ
 
Where Q = Amount of heat in J
             m = Mass of substance in kg
              θ  = Temperature rise in °C or K
              C = Specific heat capacity in J/kgK

From given data:
Q = 33 kJ = 33 000 J, m= 2.0 kg,   θ  = 80 K,   c = ?

33000 =  2 * c * 80
33000 = 160c
160c   = 33000
       c   =  33000/160 = 206.25

Therefore specific heat capacity is 206.25 J/kgK