Respuesta :
If A varies directly with z, and A is 30 and z is 5, then when z is 1, A is 6.
z: 5 ÷ 5 = 1
A: 30 ÷ 5 = 6
Then, when z is 1, A is 6
So, when z is 9, A is...
z: 1 × 9 = 9
A: 6 × 9 = 54
A is 54
z: 5 ÷ 5 = 1
A: 30 ÷ 5 = 6
Then, when z is 1, A is 6
So, when z is 9, A is...
z: 1 × 9 = 9
A: 6 × 9 = 54
A is 54
We can this two ways:
1) If A = 30 when Z = 5, then A = 6Z or A = 6*z
So if Z = 9, 9 * 6 = 54. A = 54.
2) You can set up a proportion:
[tex] \frac{30}{5} = \frac{x}{9} [/tex] where x = the unknown A-value.
Crossmultiply:
5x = 30*9
5x = 270
Divide by 5 on both sides to isolate the variable
x = 54
54 is your A value when Z = 9.
Either way you solve it, your answer is 54.
1) If A = 30 when Z = 5, then A = 6Z or A = 6*z
So if Z = 9, 9 * 6 = 54. A = 54.
2) You can set up a proportion:
[tex] \frac{30}{5} = \frac{x}{9} [/tex] where x = the unknown A-value.
Crossmultiply:
5x = 30*9
5x = 270
Divide by 5 on both sides to isolate the variable
x = 54
54 is your A value when Z = 9.
Either way you solve it, your answer is 54.