Question

simplify the complex function (n-3/n^2+6n+8)/(n+1/n+2)

Answer 1

$\bf \cfrac{\quad \frac{n-3}{n^2+6n+8}\quad }{\frac{n+1}{n+2}}\implies \cfrac{\quad \frac{n-3}{(n+4)(n+2)}\quad }{\frac{n+1}{n+2}}\implies \cfrac{n-3}{(n+4)\underline{(n+2)}}\cdot \cfrac{\underline{n+2}}{n+1} \\\\\\ \cfrac{n-3}{(n+4)(n+1)}\implies \cfrac{n-3}{n^2+5n+4}$