[tex]\bf \cfrac{x^2+5x+6}{x+4}\cdot \cfrac{x^2+x-12}{x^2+x-2}\implies \cfrac{\underline{(x+2)}(x+3)}{\underline{x+4}}\cdot \cfrac{\underline{(x+4)}(x-3)}{\underline{(x+2)}(x-1)}
\\\\\\
\cfrac{(x+3)(x-3)}{x-1}[/tex]
and yes, the restrictions are -4, -2 and 1.
the original expression has such restrictions because if ever "x" becomes one of those values, one of the denominators will turn to 0 making the fraction undefined.
