Respuesta :
[tex] {7}^{2} + {1}^{2} = 50 \\ \sqrt{50} = 7.07[/tex]
the answer is 7.1
The length of a line segment FE will be 7.07 m. It is obtained by its specified formula, which is distance between the two points in a coordinate system.
How far apart are the points (x₁, y₁) and (x₂, y₂)?
Between points (x₁, y₁) and (x₂, y₂). The shortest distance (length of the straight line segment connecting both specified locations is;
[tex]\rm D = \sqrt{(x_2-x_1)2 + (y_2-y_1)2}\\\\ \rm D = \sqrt{(4-(-3))^2 + (4-3)2}\\\\ D=\sqrt{7^2+1^2} \\\\\ D=\sqrt{50} \\\\ D=7.07 \ m[/tex]
The length of a line segment FE will be 7.07 m.
Learn more about the distance between two points;
brainly.com/question/16410393
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