Question

What are the solutions of 3x^2-x+4=0

Answer 1

There is no real solution

What is a quadratic equation?

An equation whose highest degree is 2 is called a quadratic equation.

How to solve a quadratic equation?

We can solve a quadratic equation by two ways:

• Factorization- If the quadratic expression is factorizable then we can factorize it and equate it to 0. Then we can apply the concept that when product of two or more expressions is 0 then at least one of the expression or both must be 0
• By Shreedhar Acharya formula- A quadratic equation of the form $ax^{2} +bx+c=0$ can be solved by the formula given below:

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}$    or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

The given problem can be solved by the Shreedhar Acharya formula :

$3x^{2} -x+4=0$

• Comparing it to the standard equation $ax^{2} +bx+c=0$, we can write,

              a=3

              b=-1

              c=4

⇒$x=\frac{-(-1)+\sqrt{(-1)^{2}-4(3)(4)} }{2(3)}$

or  $x=\frac{-(-1)-\sqrt{(-1)^{2}-4(3)(4)} }{2(3)}$

• Here, there is no real solution because a negative term is coming under square root.
• There are imaginary solutions for this equation

You can get more solutions on: https://brainly.com/question/1214333

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