Question

Kool-aide is made from flavored powder and water, with the ratio of powder to water 3:2 based on weight. If 120g of flavored powder are needed for a certain amount of Kool-aide, how much water will be needed for this amount?

Answer 1

The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.

Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter $x$. Thus, from the given information we can conclude that:

$\frac{Powder Weight}{Water Weight}=\frac{3}{2}=\frac{120}{x}$

$\therefore \frac{3}{2}=\frac{120}{x}$

Cross-multiplying we get:

$3x=240$

$\therefore x=\frac{240}{3}=80$ grams.

Thus, the amount of water in grams in that Kool-aide is 80 grams.