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In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many lone pairs of electrons are present in the Lewis structure of calcium sulfide?

Respuesta :

 Calcium Sulfide is an ionic compound made up of Ca²⁺ and S²⁻.Ca²⁺ is formed as,
                                   Ca    →    Ca²⁺  +  2 e⁻
These two electrons are accepte by Sulfur as,
                                     S  +  2 e⁻    →    S²⁻
So, before accepting 2 electrons S was having six valence electrons, after accepting two electrons from Ca it has 8 electrons which are present in four pairs.

Answer:  On Plato the correct answer is NOT D. four

Explanation:  I got it wrong.  Hope you have better luck