Question

Find the value of x in each case. PLEASE SHOW WORK!!!

Answer 1

Hi,
$mes \widehat{BCE}=90^o-64^o=36^o\\ mes \widehat{ABE}=mes \widehat{BEC}+mes \widehat{BCE}\\ 3x=x+36\\ \Rightarrow\ 3x-x=36\\ \Rightarrow\ 2x=36\\ \Rightarrow\ x= \dfrac{36}{2} \\ \Rightarrow\ \boxed{x=18}$