Question

please answer this im dying here

Answer 1

$t\geq-273\\\\ 358=20\sqrt{273+t}\\ 17.9=\sqrt{273+t}\\ 320.41=273+t\\ t=47.41\approx47$

Answer 2

$v=20\sqrt{273+t};\ t > 0$
We have
$v=358\ m/s$
substitute
$20\sqrt{273+t}=358\ \ \ |:20\\\\\sqrt{273+t}=17.9\ \ \ |square\ both\ sides\\\\273+t=320.41\ \ \ \ |-273\\\\t=47.41\approx47$
Answer: 47°C