Let [tex]p_i=0.1[/tex] be a probability that i-th light fails, where i=1,2,3. Then, [tex]q_i=1-p_i=1-0.1=0.9 [/tex] is the probability that i-th light remain bright.
If the lights fail independently of each other, the probability that a string of lights will remain bright for two years is:
[tex]q_1q_2q_3=(0.9)^3=0.729 [/tex].