Question

There are 36 ways two dice can land: six ways for the first die and six ways for the second die. in how many of those ways does at least one of the dice show a 6?

Answer 1

I believe it is 6 ways:

6 & 1
6 & 2
6 & 3
6 & 4
6 & 5
6 & 6

Answer 2

The ways do at least one of the dice show a 6 is 11 which is given below.

$\rightarrow 11 = \{(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)(1,6)(2,6)(3,6)(4,6)(5,6)\}$

What is the sample?

A sample is the collection of well-defined elements. A sample is represented by a capital letter symbol and the number of elements in the finite set is shown as curly bracket {..}.

There are 36 ways two dice can land:

six ways for the first die and six ways for the second die.

All the possibilities will be given below.

$(1,1) (1,2)(1,3)(1,4)(1,5)(1,6)\\\\(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)\\\\(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)\\\\(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)\\\\(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)\\\\(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)$

The ways do at least one of the dice show a 6 will be

$\rightarrow 11 = \{(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)(1,6)(2,6)(3,6)(4,6)(5,6)\}$

More about the sample link is given below.

https://brainly.com/question/350477