Question

what is the equation of a circle with a center located at 0, -2 in a circumference of 16*3.14

Answer 1

circumference = 3.14 * 2 * r  = 3.14 * 16  so r = 8

general equation is  (x - a)^2 + (y - b)^2 = r^2

So our Equation is   x^2 + (y + 2)^2 = 64  (answer)