Question

a wire of length 5.0m and diameter 2.0mm extends by 0.25mm when a force of 50N was used to stretch it from its end calculate the stress on the wire and strain on the wire take
$\pi = 3.142$

Answer 1

Calculate:
(i) stress 
(ii) strain in the wire (pi=3.142)

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stress = force/area = 50/(PI*.02^2) N/M^2 

strain = extension/length = 2.5E-4/5 
= .5E-4