Question

Simplify the expression “the square root of 2003-04-04-00-00_files/i0300000.jpg times the square root of 2003-04-04-00-00_files/i0300001.jpg” completely.

Answer 1

In the form of a formula this is:





Some things to consider:

Ax * Ay = Ax+y

(Ax)y = Ax*y

And Square-root of x is equal to x(1/2)



So this forumula is equivalent to:

(x^10)^1/2 * (x^4)^1/2

= x^(10/2) * x^(4/2)

= x^5 * x^2

= x^(5 + 2)

= X^7