Question

** ANSWER QUICKLY TIMED QUIZ **

determine which equation has the same solutions as the equation below: 4x^2+32x-28=0

options:

A: 4(x+8)^2=28
B: (x+4)^2=23
C: 4(x+4)^2=36
D: (x+8)^2=57

Answer 1

$4x^2+32x-28=0\ \ \ |:4\\\\x^2+8x-7=0\ \ \ |+7\\\\x^2+8x=7\\\\x^2+2x\cdot4=7\ \ \ |+4^2\\\\x^2+2x\cdot4+4^2=7+4^2\\\\(x+4)^2=7+16\\\\(x+4)^2=23\\\\Answer:\ B.(x+4)^2=23$

Answer 2

The required equation gives the same solution as the equation $4x^2+32x-28=0$ is $(x+4)^2=23$. Option B is correct.

Given that,
The equation given $4x^2+32x-28=0$ the same equation is to be determined that gives the same solution as the equation above.

What are functions?

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

Here,
$4x^2+32x-28=0$
the dividing the whole equation by 4.
$x^2+8x-7=0\\x^2 + 8x +16 - 16 - 7 = 0\\(x + 4)^2 -23 = 0\\(x + 4 )^2 = 23$

Thus, the required equation gives the same solution as the equation $4x^2+32x-28=0$ is $(x+4)^2=23$. Option B is correct.

Learn more about function here:

brainly.com/question/21145944

#SPJ5