[tex] \frac{3}{4} ( \frac{1}{2} x-12)+ \frac{4}{5} =[/tex]
[tex] =\frac{3}{4} ( \frac{x}{2} -12)+ \frac{4}{5} [/tex]
[tex] = \frac{3x}{8} -9+ \frac{4}{5} [/tex]
[tex] = -\frac{41}{5} + \frac{3x}{8} [/tex]
The answer is: [tex] -\frac{41}{5} + \frac{3x}{8} [/tex]
