Respuesta :
see the attached picture to better understand the problem
we know that
∠PML=90°
∠KML=54°
∠KMP+∠KML=90°------------> by complementary angles
so
∠KMP=90-54-----> ∠KMP=36°
∠NKM=∠KML
∠NKM=54°
so
the angle bisector of ∠NKM =∠PKM
∠PKM=∠NKM/2-----> ∠PKM=54/2--------> ∠PKM=27°
we know that
the sum of the internal angles of a triangle is equal 180 degrees
in the triangle PKM
∠PKM+∠KPM+∠KMP=180°
∠KPM=180-[∠PKM+∠KMP]-----> 180-[27+36]----> 117°
∠KPM=117°
the answer is
∠KPM is 117°
we know that
∠PML=90°
∠KML=54°
∠KMP+∠KML=90°------------> by complementary angles
so
∠KMP=90-54-----> ∠KMP=36°
∠NKM=∠KML
∠NKM=54°
so
the angle bisector of ∠NKM =∠PKM
∠PKM=∠NKM/2-----> ∠PKM=54/2--------> ∠PKM=27°
we know that
the sum of the internal angles of a triangle is equal 180 degrees
in the triangle PKM
∠PKM+∠KPM+∠KMP=180°
∠KPM=180-[∠PKM+∠KMP]-----> 180-[27+36]----> 117°
∠KPM=117°
the answer is
∠KPM is 117°

The measure of ∠KPM comes to be 117°.
Find the attached picture to visualize the problem.
Since KP is the angle bisector
So, ∠NKP =∠PKM = 54/2
∠PKM = 27°
It is given that
∠KML = 54°
So, ∠KML = 90-54 = 36°
What is the sum of interior angles of a triangle?
The sum of interior angles of a triangle is 180°.
So, ∠KPM + ∠PKM + ∠KMP = 180°
∠KPM + 27°+ 36° = 180°
∠KPM = 180°-(27°+ 36°) = 117°
Therefore, the measure of ∠KPM comes to be 117°.
To get more about rectangles visit:
https://brainly.com/question/1168982

