Respuesta :
[tex]a_n=48+3(2n-1)[/tex]
The formula of the sum of the arithmetic sequence:
[tex]S_n=\dfrac{a_1+a__n}{2}\cdot n[/tex]
calculate:
[tex]a_1=48+3(2\cdot1-1)=48+3=51[/tex]
substitute
[tex]S_n=\dfrac{51+48+3(2n-1)}{2}\cdot n=\dfrac{99+6n-3}{2}\cdot n=\dfrac{96+6n}{2}\cdot n=3n^2+48n[/tex]
Your answer is:
[tex]\boxed{f(x)=3x^2+48x}[/tex]
The formula of the sum of the arithmetic sequence:
[tex]S_n=\dfrac{a_1+a__n}{2}\cdot n[/tex]
calculate:
[tex]a_1=48+3(2\cdot1-1)=48+3=51[/tex]
substitute
[tex]S_n=\dfrac{51+48+3(2n-1)}{2}\cdot n=\dfrac{99+6n-3}{2}\cdot n=\dfrac{96+6n}{2}\cdot n=3n^2+48n[/tex]
Your answer is:
[tex]\boxed{f(x)=3x^2+48x}[/tex]