The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?
The answer is (c) (30,401). The given time, 10 seconds, is plugged into the given parametric equations for the path of a rocket ship: x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch.