Question

The area of ΔABC = 14 ft2. If side a = 5 ft and angle C = 53°, find the measure of side b. Round your answer to the nearest tenth.

Answer 1

Area of triangle = (1/2)*a*b*sin(C)
14 = (1/2)*5*b*sin(53)
14 = (1/2)*5*sin(53)*b
14 = 1.99658877511823*b
b = 14/1.99658877511823
b = 7.01195968567488
b = 7.0

Side b is roughly 7.0 ft