I used the generic rectangle/diamond method, although the quadratic formula would work just as well with a=3, b=11, c=6. Put that into the quadratic formula[tex] \frac{-b+/- \sqrt{b ^{2}-4ac } }{2a} [/tex] to get that your factors are x = -2/3 and -3. Putting those into factorization form you get the 2 factors as (3x+2)(x+3)
