Question

solve for x in the equation x^2-8x+41=0

Answer 1

x=​2​​8+10ı​​,​2​​8−10ı​​  

x=4+5ı,4−5ı

hope this helps the bottom one is the answer :)

Answer 2

x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  

x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2

 4 +or- 5i