Respuesta :
[tex]\text{A quadratic function:}\ f(x)=ax^2+bx+c\\\\\text{where}\ a\neq0[/tex]
[tex]f(x)+-8x^3-16x^2-4x-NOT\\\\f(x)=x^2+2x-5-YES\\\\f(x)=?+1-NOT\\\\f(x)=0x^2-9x+7-NOT[/tex]
[tex]f(x)+-8x^3-16x^2-4x-NOT\\\\f(x)=x^2+2x-5-YES\\\\f(x)=?+1-NOT\\\\f(x)=0x^2-9x+7-NOT[/tex]
Answer:
[tex]f(x)=x^{2} +2x-5[/tex]
Step-by-step explanation:
We need to find the function [tex]f(x)[/tex] representing a quadratic function.
Now, we know that the general form of a quadratic function is [tex]ax^{2}+bx+c[/tex] , where [tex]a\neq 0[/tex]
So, Let us consider each function one by one.
[tex]f(x)=-8x^{3}-16x^{2} -4x[/tex]
Clearly, the above function has a cubic term in it so it is a cubic function NOT a quadratic function.
Now, [tex]f(x)=x^{2} +2x-5[/tex]
Clearly, the above function is of the form [tex]ax^{2}+bx+c[/tex] so, it is a quadratic function.
Now, [tex]f(x)=0x^{2} -9x+7[/tex]
Here, the coefficient of [tex]x^{2}[/tex] is 0. So, it is not of the form [tex]ax^{2}+bx+c[/tex] , where [tex]a\neq 0[/tex] .
So, it is NOT a quadratic function.
Hence, only [tex]f(x)=x^{2} +2x-5[/tex] is a quadratic function among the all functions.