Respuesta :
To solve this problem you must apply the proccedure shown below:
The total volume of the art box not taken up by the eraser is:
Vt=V(artbox)-V(eraser)
V(eraser)=0.25 inchesx1 inchx2 inches
V(eraser)=0.5 inches³
V(artbox)=5 inchesx8 inchesx2 inches
V(artbox)=80 inches³
Vt=80 inches³-0.5 inches³
Vt=79.5 inches³
The answer is: 79.5 inches³
The total volume of the art box not taken up by the eraser is:
Vt=V(artbox)-V(eraser)
V(eraser)=0.25 inchesx1 inchx2 inches
V(eraser)=0.5 inches³
V(artbox)=5 inchesx8 inchesx2 inches
V(artbox)=80 inches³
Vt=80 inches³-0.5 inches³
Vt=79.5 inches³
The answer is: 79.5 inches³
Answer:
The answer is 1196 cm^3
Step-by-step explanation:
First let's find the volume of the art box.
V = lwh
V = 20 * 12 * 5
V = 1200
Now let's find the volume taken up by the eraser.
V = lwh
V = 4 * 2 * 0.5
V = 4
We can subtract to find the volume of the box that is not taken up by the eraser.
1200 - 4 = 1196cm^3