Lest solve our inequality first:
[tex]7-9x-(x+12) \leq 25[/tex]
[tex]7-9x-x-12 \leq 25[/tex]
[tex]-10x-5 \leq 25[/tex]
[tex]-10x \leq 30[/tex]
[tex]x \geq \frac{30}{-10} [/tex]
[tex]x \geq -3[/tex]
We can conclude that x less than or equal to −3 is not a way to represent the solution of the inequality 7 − 9x − (x + 12) less than or equal to 25.