Question

An alloy is composed of nickel, zinc, and copper in a ration of 7:2:9. How many kilograms of each metal are needed to make 3.6kg of this alloy?

Answer 1

well, the short answer is, we divide that 3.6 by (7+2+9) and then we give as many pieces at the ratio to each, so let's do so,

$\bf \stackrel{nickel}{7}~~:~~\stackrel{zinc}{2}~~:~~\stackrel{copper}{9} \\\\\\ \stackrel{nickel}{7\cdot \frac{3.6}{7+2+9}}~~:~~\stackrel{zinc}{2\cdot \frac{3.6}{7+2+9}}~~:~~\stackrel{copper}{9\cdot \frac{3.6}{7+2+9}} \\\\\\ \stackrel{nickel}{7\cdot 0.2}~~:~~\stackrel{zinc}{2\cdot 0.2}~~:~~\stackrel{copper}{9\cdot 0.2} \\\\\\ \stackrel{nickel}{1.4}~~:~~\stackrel{zinc}{0.4}~~:~~\stackrel{copper}{1.8}$

Answer 2

The amount of nickel, zinc, and copper that is needed to be mixed to make an alloy of 3.6 kg is 1.4kg, 0.4 kg, and 1.8kg, respectively.

What is a Ratio?

A ratio shows us the number of times a number contains another number.

Let the amount of nickel, zinc, and copper be 7x, 2x, and 9x.

The sum of the metals that are needed to make an alloy of 3.6 kgs, can be written as,

7x + 2x + 9x = 3.6 kg

18x = 3.6

x = 0.2

Now, the amount of metal can be written as,

Nickel, 7x = 7 × 0.2 = 1.4 kg

Zinc, 2x = 2 × 0.2 = 0.4 kg

Copper, 9x = 9 × 0.2 = 1.8 kg

Hence, the amount of nickel, zinc, and copper that is needed to be mixed to make an alloy of 3.6 kg is 1.4kg, 0.4 kg, and 1.8kg, respectively.

Learn more about Ratios:

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