Question

In ​ Quadrilateral ABCD, AB∥CD and m∠2=27.

What is m∠5?

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Answer 1

Quadrilateral ABCD, AB∥CD
m∠2=27 so m<5 = 27 (alternate interior angles are equal)

Answer
m∠5=27

Answer 2

Answer:$\angle5$ = 27°

Explanation:

Given: ABCD is a  Quadrilateral and AB is parallel to CD and $\angle 2$=27 degree

We have to find out: $\angle 5$

since, AB is parallel to CD , and according to the properties of parallel lines If two parallel lines are cut by a transversal line then the alternative interior angles made by that transerversal are always equal.

here BD makes the transversal line for parallel lines AB and CD. and $\angle 2$ and$\angle 5$ are interior angles of lines CD and AB respectively. And these angle are alternative to each other.

Thus they must have the equal values. This implies if $\angle 2$ = 27° then $\angle 5$= 27°