Answer:
[tex]\sqrt{-80}=4i \sqrt{5}[/tex]
Step-by-step explanation:
We know that [tex]\sqrt{-1}=i[/tex]
Here we need to find [tex]\sqrt{-80}[/tex]
Let us simplify
[tex]\sqrt{-80}=\sqrt{-1\times 80}=\sqrt{-1}\times \sqrt{80}=i\sqrt{16\times 5}\\\\\sqrt{-80}=i\times \sqrt{16}\times \sqrt{5}=i\times 4\times \sqrt{5}=4i \sqrt{5}\\\\\sqrt{-80}=4i \sqrt{5}[/tex]