Question

What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)?

Answer 1

Hi there! The answer is y = x - 1

The general equation of a line in slope-intercept form is y = ax + b, with a representing the slope. Since this line is parallel to y = x + 4, the value of a (the slope) = 1.

Hence, y = 1x + b = x + b.
The line passes through the point (6, 5), so we can plug in the 6 at x and the 5 at y.

5 = 6 + b
Subtract 6.

- 1 = b
Switch sides.

b = - 1.
And therefore the answer is y = x - 1

~ Hope this helps you!

Answer 2

The equation of the straight line that is parallel to the line  $y = x + 4$ and passes through the point (6, 5) is $y = x - 1$.

What is the general equation of a straight line?

The general equation of a straight line is $y = mx + c$.

Here, (x, y) is the coordinate through which the line passes. 'm' is the slope of the line and 'c' is the y-intercept.

The required line is parallel to the line $y = x + 4$.

Therefore, the slope of the required line(m) is 1.

The required line passes through the point (6, 5).

Therefore, putting the values in the general equation, we get:

$5 = 6 (1) + c$

⇒ $c = - 1$

Therefore, the required equation of the straight line is:

$y = x - 1$

Learn more of a straight line here:

https://brainly.com/question/9068341

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