Answer:
The correct option is D.
Step-by-step explanation:
The given function is
[tex]y=2\cos (3x-2\pi)[/tex] .... (1)
The general form of cosine function is
[tex]y=A\cos (Bx-C)+D[/tex] ... (2)
Where, A is amlitude, 2π/B is period, C is phase shift and D is midline.
From equation (1) and (2), we get
[tex]B=3[/tex]
The period of the function is
[tex]period=\frac{2\pi}{B}=\frac{2\pi}{3}[/tex]
Therefore the correct option is D.
