Question

Write the first 6 terms of an arithmetc sequence if the first number is 9 and the common diffrence is 5

Answer 1

$a_1=9\\d=5\\\\a_n=a_1+(n-1)d\\\\a_n=9+(n-1)\cdot5\\\\a_n=9+5n-5\\\\a_n=5n+4\\\\a_1=9\\a_2=5\cdot2+4=14\\a_3=5\cdot3+4=19\\a_4=5\cdot4+4=24\\a_5=5\cdot5+4=29\\a_6=5\cdot6+4=34$