Question

please help asap 30 pts

Answer 1

Factoring the numerator, we get 3(x-9).  Factoring the denom., we get 3(x+1).

Simplifying

 3(x-9)                     x-9
-----------    we get --------
3(x+1)                     x+1

Answer 2

$\dfrac{3x-27}{3x+3}=\dfrac{3\cdot x-3\cdot9}{3\cdot x+3\cdot1}=\dfrac{3(x-9)}{3(x+1)}=\dfrac{\not3^1(x-9)}{\not3^1(x+1)}=\dfrac{x-9}{x+1}\\\\\boxed{Answer:\ \dfrac{x-9}{x+1}}$