So we are given in the question the surface area of the curved part:
[tex]SA= \pi rl[/tex]
We have those values already, so we can readily solve for that:
[tex]SA= \pi (5)(9)=45 \pi [/tex]
And the question said to leave it in terms of [tex] \pi [/tex], so we do not need to simplify further.
Let us solve for the base now. The base is a circle, and we know that the area of a circle is found using the equation:
[tex]A= \pi r^{2} [/tex]
We can also readily solve for this using 5 for r:
[tex]A= \pi (5)^{2} =25 \pi [/tex]
And now that we have both surfaces, we can add them together to find the total surface area:
[tex]SA=45 \pi +25 \pi =70 \pi [/tex]
So now we know that the total surface area of this cone is [tex]70 \pi [/tex].