Respuesta :
So first we need to find the slope. The equation find slope is:
[tex] \frac{ y_{2} -y_{1} }{ x_{2}- x_{1} } [/tex]
Either of the points could be denoted as '1' or '2',
Let's plug in the point (0, 8) as '1' and (-1, 10) as '2':
[tex] \frac{10-8}{-1-0} = \frac{2}{-1}=-2 [/tex]
So we know that the slope, m, is equal to -2.
The point-slope equation is:
[tex]y- y_{1}=m(x- x_{1}) [/tex]
where m is the slope and [tex] x_{1} [/tex] and [tex] y_{1} [/tex] are the point. So since we have two points here, we can pick one to use for the equation. Let's use (-1, 10):
[tex]y-(10)=-2(x-(-1))[/tex]
**We need to make sure that we have accounted for all of the signs. Remember that two negatives equal a positive:
[tex]y-10=-2(x+1)[/tex]
And there is your point slope form of the line that passes through the two points.
[tex] \frac{ y_{2} -y_{1} }{ x_{2}- x_{1} } [/tex]
Either of the points could be denoted as '1' or '2',
Let's plug in the point (0, 8) as '1' and (-1, 10) as '2':
[tex] \frac{10-8}{-1-0} = \frac{2}{-1}=-2 [/tex]
So we know that the slope, m, is equal to -2.
The point-slope equation is:
[tex]y- y_{1}=m(x- x_{1}) [/tex]
where m is the slope and [tex] x_{1} [/tex] and [tex] y_{1} [/tex] are the point. So since we have two points here, we can pick one to use for the equation. Let's use (-1, 10):
[tex]y-(10)=-2(x-(-1))[/tex]
**We need to make sure that we have accounted for all of the signs. Remember that two negatives equal a positive:
[tex]y-10=-2(x+1)[/tex]
And there is your point slope form of the line that passes through the two points.