payshencec21
payshencec21
29-05-2018
Mathematics
contestada
please help asap 25 pts
Respuesta :
gmany
gmany
29-05-2018
[tex]y=ax^2+bx+c\\\\\text{Axis of symmetry:}\ x=\dfrac{-b}{2a}[/tex]
[tex]\text{We have:}\\\\y=4x^2+16x-18\\\\a=4;\ b=16;\ c=-18\\\\x=\dfrac{-16}{2\cdot4}=\dfrac{-16}{8}=-2[/tex]
Answer: A.
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