Respuesta :

3x² -16x-12 =0

We can solve this equation using formula.

a=3, b=-16, c=-12

[tex]x= \frac{-b+/- \sqrt{b^{2} -4ac} }{2a} \\ \\ x= \frac{16+/- \sqrt{16^{2}+4*3*12} }{2*3} = \frac{16+/- \sqrt{400} }{6} = \frac{16+/-20}{6} \\ \\ x_{1}= \frac{16+20}{6} =6 \\ \\x_{2}= \frac{16-20}{6} =- \frac{4}{6} = -\frac{2}{3} [/tex]
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