Question

How many grams of hydrogen are needed to produce 15.0 mol of ammonia if the reaction goes to completion?

Answer 1

Reaction involved in present system is :  N2   +    3H2     →    2NH3

In present reaction, 1 mol of N2 react with 3 moles of H2 to generate 2 moles of NH3

Thus, 2 moles of NH3 ≡ 3 moles  of H2
Therefore, 15 moles of NH3 ≡ (3X15)/2 = 22.5 moles of H2.

We know that, 1 mole of H2 ≡ 2 g
Therefore, 22.5 moles of H2 ≡ 2 X 22.5 = 45 g

Thus, 45 g of hydrogen are needed to produce 15.0 mol of ammonia, if the reaction goes to completion

Answer 2

45 grams of hydrogen are needed to produce 15.0 mole of ammonia if the reaction goes to completion.

What is hydrogen?

Hydrogen is a chemical element with the chemical symbol H whose atomic number is 1.

It is a diatomic gas.

Given,

The reaction is

$\bold{N_2 + 3H_2= 2NH_3}$

One mole of nitrogen reacts with 3 moles of hydrogen to produce two moles of ammonia.

If 2 moles of ammonia = 3 moles of hydrogen.

Therefore, 15 moles of ammonia = $\dfrac{3 \times15}{2 } = 22.5\; moles\; of\; H_2.$

1 mole of hydrogen is 2 g

Therefore, for 22.5 moles of hydrogen

$22.5 \times 2 = 45\;grams$

Thus, 45 grams of hydrogen are needed.

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Thus, 45 g of hydrogen are needed to produce 15.0 mol of ammonia, if the reaction goes to completion