A truck driver earns a daily amount based on the number of miles he drives on Monday here and $70 for driving 120 miles and on Tuesday he earns $102.50 for driving to 50 miles explain how to derive A linear function that expresses the daily amount she earns fir driving X miles that day show your work and intercept the rate of change and initial value of the function.

Respuesta :

Let x represent miles and y represent dollars.
That gives you coordinates (120, 70) and (50, 102.5).
First, find the slope (m) of the line using [tex] \frac{y_{2} - y_{1} }{ x_{2} - x_{1}} [/tex]
m = [tex] \frac{70 - 102.5}{120 - 50} [/tex]
    = [tex] \frac{-32.5}{70} [/tex] = [tex] \frac{-65}{140} = \frac{-13}{28} [/tex]
Note: slope is rate of change.

Next, use the Point-Slope formula and solve for y:
y - [tex] y_{1} [/tex] = m (x - [tex] x_{1} [/tex])
y - 70 = [tex] \frac{-13}{28} [/tex](x - 120)
y - 70 = [tex] \frac{-13}{28} [/tex]x + [tex] \frac{390}{7} [/tex]
      y  = [tex] \frac{-13}{28} [/tex]x + [tex] \frac{880}{7} [/tex]

Answer:
linear function is: y  = [tex] \frac{-13}{28} [/tex]x + [tex] \frac{880}{7} [/tex]
rate of change is: [tex]\frac{-13}{28} [/tex]
initial value of the function: [tex] \frac{880}{7} [/tex]







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