Question

Find the mean,variance, and standard deviation of the binomial distribution with the given values n=129 p=0.29

Answer 1

n= 129
p=0.29
then q=1-p= 1-0.29=0.71
for binomial distribution
variance=npq= 129 × 0.29 × 0.71
mean= np= 129×0.29
standard deviation= square root of variance=
$\sqrt{variance} =$
$\sqrt{npq}$