Question

Find the sum of 2x^2 + 3x - 4, 8 - 3x, and -5x^2 + 2.
A) -3x^2 - 2
B) -7x^2 - 2
C) -3x^2 + 6
D) -7x^2 - 6x - 2

Answer 1

$(2x^2+3x-4)+(8-3x)+(-5x^2+2)\\\\=(2x^2-5x^2)+(3x-3x)+(-4+8+2)\\\\=-3x^2+6$

$Answer:\ C)\ -3x^2+6}$