Question

What is the third quartile of this data set?

14, 18, 20, 21, 25, 32, 42, 46, 48
A. 32
B. 42
C. 44
D. 43

Answer 1

Divide the list of numbers in half.
Since there are 9 numbers (odd number), divide like this :

14, 18, 20, 21      25       32, 42, 46, 48

Find the median of the third one. 
(46 + 42)/2 = 44

So the answer is C. 44
Hope this helped!

Answer 2

Answer with Step-by-step explanation:

When number of terms are odd the quartiles are the terms

$Qi=i\times \dfrac{n+1}{4}\ th\ term$

Here we have to calculate the third quartile i.e. i=3

and number of terms are 9

i.e. n=9

$Q3=3\times \dfrac{n+1}{4}\ th\ term$

Q3=7.5 th term

7 th term=42

8 th term=46

7.5 th term is the mean of 7 th and 8 th term

= (42+46)/2

= 44

Hence, Correct option is:

C. 44