Respuesta :

Use the double angle identity:


[tex]\sin^2\dfrac\pi{12}=\dfrac{1-\cos\frac\pi6}2[/tex]


Then [tex]\cos\dfrac\pi6=\dfrac{\sqrt3}2[/tex], so you get


[tex]\sin^2\dfrac\pi{12}=\dfrac{2-\sqrt3}4[/tex]
RELAXING NOICE
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