The electric field strength will be 2.81 ×10⁵ N/C. Electric field strength is obtained by dividing the electric force to the charge.
The electric field strength is defined as the ratio of electric force and charge.
The given data in the problem is;
The charge is,q= 6.4 ×10⁻⁷ C
The electric force is,F=1.8 ×10⁻¹ N
The electric file strength is,E=?
The electric field strength is found as;
[tex]\rm E = \frac{F}{q} \\\\ \rm E = \frac{1.8 \times 10^{-1}}{6.4 \times 10^{-7}} \\\\ E= 2.81 \TIMES 10^{5} \ N/C[/tex]
The electric field strength will be 2.81×10⁵ N/C.
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